if you want to remove an article from website contact us from top.

# two objects, x and y, accelerate from rest with the same constant acceleration. object x accelerates for twice the time as object y. which of the following is true of these objects at the end of their respective periods of acceleration?

Category :

### James

Guys, does anyone know the answer?

get two objects, x and y, accelerate from rest with the same constant acceleration. object x accelerates for twice the time as object y. which of the following is true of these objects at the end of their respective periods of acceleration? from EN Bilgi.

Let speed of object X be ${v}_{x}$vx

Let speed of object Y be ${v}_{y}$vy

Let acceleration be $a$a

Let time of acceleration of object X be ${t}_{x}$tx

Let time of acceleration of object Y be ${t}_{y}$ty

${v}_{y}=0+a{t}_{y}$vy=0+aty

ty=avy                                   (1)

${v}_{x}=0+a{t}_{x}$vx=0+atx

tx=avx                                   (2)

tx=3ty                                   (3)

from equation (1),(2) and (3)

${v}_{x}=3{v}_{y}$vx=3vy

$\therefore$ The final speed of object X is three times faster than object Y

${v}_{x}^{2}=2a{s}_{x}$vx2=2asx

${v}_{y}^{2}=2a{s}_{y}$vy2=2asy

${v}_{x}^{2}=9{v}_{y}^{2}$vx2=9vy2

sx=9sy

Object X has travelled nine times as far as object Y

Source : www.assignmentexpert.com

## Accelerate for twice the time

Two objects, A and B, are accelerated from rest with the same constant acceleration. However, object A is accelerated for twice as much time as object B. Which one of the following statements is true?

Source : media.ed.science.psu.edu

## Objects A and B both start from rest. They both accelerate at the same rate. However object A accelerates for twice the time as object B. Now, the distance traveled by object A compared to that of object B is four times as far. How was this derived?

The kinematic equation that works best for this is:

s = ut + 1/2 a t^2

63 = 12 t + 1/2 (6) t^2

63 = 12 t + 3 t^2

3 t^2 +12 t - 63 = 0

Divide each side by 3…

t^2 +4 t -21 = 0

Factoring…

(t+7)(t-3) = 0

So, either

t+7 = 0

t -3 = 0

Therefore

Either

t = -7

t = 3

Choose t = 3 for the only realistic answer for this situation.

It takes 3 seconds to go 63 meters.

Source : www.quora.com

Do you want to see answer or more ?
James 12 month ago

Guys, does anyone know the answer?