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    two objects, x and y, accelerate from rest with the same constant acceleration. object x accelerates for twice the time as object y. which of the following is true of these objects at the end of their respective periods of acceleration?

    James

    Guys, does anyone know the answer?

    get two objects, x and y, accelerate from rest with the same constant acceleration. object x accelerates for twice the time as object y. which of the following is true of these objects at the end of their respective periods of acceleration? from EN Bilgi.

    Answer in Mechanics

    Let speed of object X be vxv_xvx

    Let speed of object Y be vyv_yvy

    Let acceleration be aaa

    Let time of acceleration of object X be txt_xtx

    Let time of acceleration of object Y be tyt_yty

    vy=0+atyv_y=0+at_yvy=0+aty

    ty=vya                                   (1)t_y=\dfrac{v_y}{a}\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space(1)ty=avy                                   (1)

    vx=0+atxv_x=0+at_xvx=0+atx

    tx=vxa                                   (2)t_x=\dfrac{v_x}{a}\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space(2)tx=avx                                   (2)

    tx=3ty                                   (3)t_x=3t_y\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space(3)tx=3ty                                   (3)

    from equation (1),(2) and (3)

    vx=3vyv_x=3v_yvx=3vy

    \therefore The final speed of object X is three times faster than object Y

    vx2=2asxv_x^2=2as_xvx2=2asx

    vy2=2asyv_y^2=2as_yvy2=2asy

    vx2=9vy2v_x^2=9v_y^2vx2=9vy2

     sx=9sy\therefore \space s_x=9s_y sx=9sy

    Object X has travelled nine times as far as object Y

    Answer in Mechanics

    Source : www.assignmentexpert.com

    Accelerate for twice the time

    Two objects, A and B, are accelerated from rest with the same constant acceleration. However, object A is accelerated for twice as much time as object B. Which one of the following statements is true?

    Accelerate for twice the time

    Source : media.ed.science.psu.edu

    Objects A and B both start from rest. They both accelerate at the same rate. However object A accelerates for twice the time as object B. Now, the distance traveled by object A compared to that of object B is four times as far. How was this derived?

    The kinematic equation that works best for this is:

    s = ut + 1/2 a t^2

    63 = 12 t + 1/2 (6) t^2

    63 = 12 t + 3 t^2

    3 t^2 +12 t - 63 = 0

    Divide each side by 3…

    t^2 +4 t -21 = 0

    Factoring…

    (t+7)(t-3) = 0

    So, either

    t+7 = 0

    t -3 = 0

    Therefore

    Either

    t = -7

    t = 3

    Choose t = 3 for the only realistic answer for this situation.

    It takes 3 seconds to go 63 meters.

    Objects A and B both start from rest. They both accelerate at the same rate. However object A accelerates for twice the time as object B. Now, the distance traveled by object A compared to that of object B is four times as far. How was this derived?

    Source : www.quora.com

    Do you want to see answer or more ?
    James 12 month ago
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    Guys, does anyone know the answer?

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