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    the interquartile range of the data set is 4. 2, 2, 3, 3, 4, 5, 5, 6, 7, 9, 12 which explains whether or not 12 is an outlier? twelve is an outlier because it is greater than the sum of 7 and 4. twelve is an outlier because it is less than the sum of 7 and 6. twelve is not an outlier because it is greater than the sum of 7 and 4. twelve is not an outlier because it is less than the sum of 7 and 6.

    James

    Guys, does anyone know the answer?

    get the interquartile range of the data set is 4. 2, 2, 3, 3, 4, 5, 5, 6, 7, 9, 12 which explains whether or not 12 is an outlier? twelve is an outlier because it is greater than the sum of 7 and 4. twelve is an outlier because it is less than the sum of 7 and 6. twelve is not an outlier because it is greater than the sum of 7 and 4. twelve is not an outlier because it is less than the sum of 7 and 6. from EN Bilgi.

    The interquartile range of the data set is 4. 2, 2

    Answer: range: 10. Measure descriptive statisticsAnswer: range: 10

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    The interquartile range of the data set is 4. 2, 2

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    The interquartile range of the data set is 4. 2, 2, 3, 3, 4, 5, 5, 6, 7, 9, 12 Which explains whether or not 12 is an outlier?

    🔴 Answer: 3 🔴 ✅ on a question ➜ The interquartile range of the data set is 4. 2, 2, 3, 3, 4, 5, 5, 6, 7, 9, 12 Which explains whether or not 12 is an outlier? - the answers to edusmarthelper.com

    12 is not an outlier because it is near by to the boundaries.

    Step-by-step explanation:

    Given : The interquartile range of the data set is 4. Data is 2,2,3,3,4,5,5,6,7,9,12.

    To find : Whether or not 12 is an outlier?

    Solution :

    Data 2,2,3,3,4,5,5,6,7,9,12

    There are 11 terms so median of the data is 6th term.

    Median = 5

    The lower quartile from 2,2,3,3,4

    Q_1=3

    The upper quartile from 5,6,7,9,12

    Q_3=7

    Q_3-Q_1=7-3=4

    Inner fence of the data is

    IQR\times 1.5=4\times 1.5=6

    Then, subtract the number from first quartile

    3-6=-3

    And Add the number to third quartile

    7+6=13

    Inner fence boundaries are -3 and 13.

    Outer fence of the data is

    IQR\times 3=4\times 3=12

    Then, subtract the number from first quartile

    3-12=-9

    And Add the number to third quartile

    7+12=19

    Inner fence boundaries are -9 and 19.

    Outliers are number that are way out of the boundaries set in both the inner and outer fence.                                

    12 is not an outlier because it is near by to the boundaries.

    The interquartile range of the data set is 4. 2, 2, 3, 3, 4, 5, 5, 6, 7, 9, 12 Which explains whether or not 12 is an outlier?

    Source : edusmarthelper.com

    The interquartile range of the data set is 4. 2, 2, 3, 3, 4, 5, 5

    The interquartile range of the data set is 4. 2, 2, 3, 3, 4, 5, 5, 6, 7, 9, 12 Which explains whether or not 12 is an outlier? Twelve is an outlier because it is greater than the sum of 7 and 4. Twelve is an outlier because it is less than the sum of 7 and 6. Twelve is not an outlier because it is greater than the sum of 7 and 4. Twelve is not an outlier because it is less than the sum of 7 and 6.

    Question :

    The interquartile range of the data set is 4. 2, 2, 3, 3, 4, 5, 5, 6, 7, 9, 12 Which explains whether or not 12 is an outlier? Twelve is an outlier because it is greater than the sum of 7 and 4. Twelve is an outlier because it is less than the sum of 7 and 6. Twelve is not an outlier because it is greater than the sum of 7 and 4. Twelve is not an outlier because it is less than the sum of 7 and 6.

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    The interquartile range of the data set is 4. 2, 2, 3, 3, 4, 5, 5

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    James 1 year ago
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