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# n moles of a diatomic ideal gas go through cycle a → b → c → d → a as shown in the figure. processes ab and cd are isothermal and occur at temperatures th and tc, respectively.

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## One mole of diatomic ideal gas undergoes a cyclic process ABC as shown in figure. The process BC is adiabatic. The temperatures at A, B and C are 400 K, 800 K and 600 K respectively. Choose the correct statement:

Click here👆to get an answer to your question ✍️ One mole of diatomic ideal gas undergoes a cyclic process ABC as shown in figure. The process BC is adiabatic. The temperatures at A, B and C are 400 K, 800 K and 600 K respectively. Choose the correct statement:

Question

A

B

C

D

## The change in internal energy in the process CA is 700R.

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Correct option is B)

For a diatomic gas,

C v ​ = 2 5 ​ R ΔU BA ​ =nC V ​ (T B ​ −T A ​ )=1× 2 5R ​ (800−400)=1000R ΔU AC ​ =ΔQ AC ​ −W AC ​ =nC P ​ (T A ​ −T C ​ )−nR(T A ​ −T C ​ )=nC V ​ (T A ​ −T C ​ )=1× 2 5R ​ (400−600)=−500R

Thus, adding up the change in internal energy in both these processes, we get change in internal energy from C to B as 500R.

As the change in internal energy is a point function we get U

BC ​ =−500R Video Explanation

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## Answered: n moles of a diatomic ideal gas go…

Solution for n moles of a diatomic ideal gas go through cycle a → b → c → d → a as shown in the figure. Processes ab and cd are isothermal and occur at…

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n moles of a diatomic ideal gas go through cycle a → b → c → d → a as shown in the figure. Processes ab and cd are isothermal and occur at temperatures TH and TC, respectively.

1) Calculate the work Wab done by the gas during the process a → b in terms of the variables in the problem.

2) Calculate the work Wbc done by the gas during the process b → c.

3) Calculate the total work W done in the entire cycle in terms of the variables in the problem.

4) Calculate the total heat Q flowing into the gas in a complete cycle.

Transcribed Image Text:a TH b d Tc V 3Va Va

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## A diatomic ideal gas goes through the cycle a

Answer to: A diatomic ideal gas goes through the cycle a-b-c-d-a as shown in the figure. Processes ab and cd are isothermal and occur at temperatures TH =...

First law of thermodynamics

## A diatomic ideal gas goes through the cycle a-b-c-d-a as shown in the figure. Processes ab and cd...

A diatomic ideal gas goes through the cycle a-b-c-d-a as shown in the figure. Processes ab and cd... Question:

A diatomic ideal gas goes through the cycle a-b-c-d-a as shown in the figure. Processes ab and cd are isothermal and occur at temperatures TH = 365 K and TC = 284 K. There are n = 35 moles of this gas in the system, and the initial volume is Va = 0.0305 m^3.

a.) Calculate the work Wab in Joules, during process b-c.

b.) Calculate the work Wbc in Joules, during process b-c.

c.) Calculate the total work W done in the entire cycle, in Joules.

d.) Calculate the total heat Q, in joules, flowing into the gas in a complete cycle.

## First Law Of Thermodynamics:

The first law of thermodynamics is the energy conservation law according to which the heat energy supplied in the system is equal to the sum of internal energy of the system and work done by the system during a cyclic process.

For the expression of the first law of thermodynamics:

Δ Q = Δ W + Δ U ΔQ=ΔW+ΔU

Here, the change in the heat of the system is

Δ Q ΔQ

Change in the internal energy of the system is

Δ U ΔU Change in work is Δ W ΔW

## Answer and Explanation:

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Highest temperature of the cycle is

T H = 365 K TH=365 K

Lowest temperature of the cycle is

T C = 284 K TC=284 K

The number of moles in the system...

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### Learn more about this topic:

First Law of Thermodynamics: Law of Conservation of Energy

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What is the first law of thermodynamics? Learn the first law of thermodynamics and its relation to the law of conservation of energy with suitable examples.

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James 8 month ago

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