if the cystic fibrosis allele protects against tuberculosis the same way the sickle-cell allele protects against malaria, then which of the following should be true of a comparison between regions with and without tuberculosis?
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get if the cystic fibrosis allele protects against tuberculosis the same way the sickle-cell allele protects against malaria, then which of the following should be true of a comparison between regions with and without tuberculosis? from EN Bilgi.
Solved Use the following passage to answer the next three
Answer to Solved Use the following passage to answer the next three
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SOLVED:Use the following passage to answer the next three questions_ It has been hypothesized that people who are heterozygous for the allele that causes the deadly genetic condition cystic fibrosis (which, among other symptoms, reduces fertility) are more resistant to the deadly disease tuberculosis _ Q5.8. If the cystic fibrosis alreie protects against tuberculosis the same way the sickle
about fibrosis and so cystic fibrosis is a auto somo, and it's recessive. So if you have a big C Lille your normal And if you have the little Scioli with the little that's the cystic fibrosis salio and to, um, actually inherit the genetic disease because cystic fibrosis has the excessively you need to be little seat little C. That's how you get the disease. All right, so we're told about a man whose father so this is the man's father has cystic fibrosis, so we don't know anything about the mother. But we know that the man himself is fina typically normal. So that means he has to have at least one big C along the little see he got from his father. So there is his mother. Um, she could be big C Big C, where she could be big C little see, we don't know, but we know that she had to have gotten a giving him a big seal. You know this man and the woman over here who's also FINA typically normal. I'll put a little dash there for just a moment, are contemplating having a child, and the child would go there. Um So this is the pedigree that's laid out for this question. Ah, and then it says to us in part B. It says, Um, what is if the population as a whole there's a fish one in 50 chance that a person assistant has These hitters I got has a has a little See Leo. What's the probability that this child here would have cystic fibrosis? Well, there's two things that we need to think about. One is, um, we don't know anything about the cystic fibrosis status of this woman other than she doesn't have it. So she could be a carrier, but she could not be a carrier. The probability that she's a carrier is one in 50. So in order for the child Sick T to get cystic fibrosis, he or she will have to get a little seal from the mother. That chance of that was that happening? This is let's using Header zygote is one in 50. Then we need to think about the probability that they actually, uh, get together and they decided to have a child. What's the probability? If they're both headers, I goes that the child would be ah, has cystic fibrosis, so we have to do upon it. Square here. Big C little C, Big C Little see then two Big sees Big See little C. Big C Little see too little sees. So the only way to have cystic fibrosis is to be home a second successive. So there's 1/4 right chance that the child would have cystic fibrosis if they're both herder cycles. So there's two sort of things have to come together. Hair one. The mother or potential mother has to be headers. I go. And then once they actually conceive a child, the child has to have gotten too little. See illegals from both parents. You do the math. That's one in 200 uh, which is about 0.5 So that's the probability the second child or the first child born would be have cystic fibrosis. And for part C, we're told, OK, if the first child has cystic fibrosis, what does that tell us? Well, it tells us right that the mother is in fact headers. I guess so. Both parents airhead arose, I guess, and so were then asked the question. What's the probability that a second child would be normal. Well, remember, there's two ways to be normal. You could get both big seal eels, or you can get the big C. They'll see combination the headers and gloves. And so you'll notice that the recorders our opponents square produce. Uh, Children with the normal Vienna type of only 1/4 produces Children with the disease. So the answer, then, is 3/4. Once we know that the mothers and carrier and we learned that because the first child has to see fibrosis, this that's a pretty straightforward thing to calculate because we can just look at our opponent square.
Tonya G.
Biology
6 months, 1 week ago
Use the following passage to answer the next three questions_ It has been hypothesized that people who are heterozygous for the allele that causes the deadly genetic condition cystic fibrosis (which, among other symptoms, reduces fertility) are more resistant to the deadly disease tuberculosis _ Q5.8. If the cystic fibrosis alreie protects against tuberculosis the same way the sickle-cell allele protects against malaria; then which of the following should be true of a comparison between regions with and without tuberculosis? Cystic fibrosis deaths should be more common in regions with tuberculosis Cystic fibrosis deaths should be less common in regions with tuberculosis _ Cystic fibrosis deaths should be equally common in both types of regions_ Regional differences in the cystic fibrosis death rate should be purely random and unpredictable.
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Answer
A rare recessive allele inherited in a Mendelian manner causes the disease cystic fibrosis. A phenotypically normal man whose father had cystic fibrosis marries a phenotypically normal woman from outside the family, and the couple consider having a child. a. Draw the pedigree as far as described. b. If the frequency in the population of heterozygotes for cystic fibrosis is 1 in $50,$ what is the chance that the couple's first child will have cystic fibrosis? c. If the first child does have cystic fibrosis, what is the probability that the second child will be normal?
Introduction to Genetic Analysis 11th (biology)
Chapter 2
Single-Gene Inheritance
Discussion
Video Transcript
about fibrosis and so cystic fibrosis is a auto somo, and it's recessive. So if you have a big C Lille your normal And if you have the little Scioli with the little that's the cystic fibrosis salio and to, um, actually inherit the genetic disease because cystic fibrosis has the excessively you need to be little seat little C. That's how you get the disease. All right, so we're told about a man whose father so this is the man's father has cystic fibrosis, so we don't know anything about the mother. But we know that the man himself is fina typically normal. So that means he has to have at least one big C along the little see he got from his father. So there is his mother. Um, she could be big C Big C, where she could be big C little see, we don't know, but we know that she had to have gotten a giving him a big seal. You know this man and the woman over here who's also FINA typically normal. I'll put a little dash there for just a moment, are contemplating having a child, and the child would go there. Um So this is the pedigree that's laid out for this question. Ah, and then it says to us in part B. It says, Um, what is if the population as a whole there's a fish one in 50 chance that a person assistant has These hitters I got has a has a little See Leo. What's the probability that this child here would have cystic fibrosis? Well, there's two things that we need to think about. One is, um, we don't know anything about the cystic fibrosis status of this woman other than she doesn't have it. So she could be a carrier, but she could not be a carrier. The probability that she's a carrier is one in 50. So in order for the child Sick T to get cystic fibrosis, he or she will have to get a little seal from the mother. That chance of that was that happening? This is let's using Header zygote is one in 50. Then we need to think about the probability that they actually, uh, get together and they decided to have a child. What's the probability? If they're both headers, I goes that the child would be ah, has cystic fibrosis, so we have to do upon it. Square here. Big C little C, Big C Little see then two Big sees Big See little C. Big C Little see too little sees. So the only way to have cystic fibrosis is to be home a second successive. So there's 1/4 right chance that the child would have cystic fibrosis if they're both herder cycles. So there's two sort of things have to come together. Hair one. The mother or potential mother has to be headers. I go. And then once they actually conceive a child, the child has to have gotten too little. See illegals from both parents. You do the math. That's one in 200 uh, which is about 0.5 So that's the probability the second child or the first child born would be have cystic fibrosis. And for part C, we're told, OK, if the first child has cystic fibrosis, what does that tell us? Well, it tells us right that the mother is in fact headers. I guess so. Both parents airhead arose, I guess, and so were then asked the question. What's the probability that a second child would be normal. Well, remember, there's two ways to be normal. You could get both big seal eels, or you can get the big C. They'll see combination the headers and gloves. And so you'll notice that the recorders our opponents square produce. Uh, Children with the normal Vienna type of only 1/4 produces Children with the disease. So the answer, then, is 3/4. Once we know that the mothers and carrier and we learned that because the first child has to see fibrosis, this that's a pretty straightforward thing to calculate because we can just look at our opponent square.
If the cystic fibrosis allele protects against tuberculosis the same way the sickle
If the cystic fibrosis allele protects against tuberculosis the same way the sickle-cell allele protects against malaria, then which of the following should be true of a comparison between regions with and without tuberculosis?
A. Cystic fibrosis deaths should be more common in regions with tuberculosis.
B. Cystic fibrosis deaths should be less common in regions with tuberculosis.
C. Cystic fibrosis deaths should be equally common in both types of regions.
D. Regional differences in the cystic fibrosis death rate should be purely random and unpredictable.
Answer:
A. Cystic fibrosis deaths should be more common in the regions with tuberculosis.
Cystic fibrosis is a genetic disorder that affects mostly the lungs. Long-term issues include difficulty in breathing and coughing up mucus from lung infections. In a region where tuberculosis is present, cyctic fibrosis death will increase.
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