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    a 1.8-m-tall diver is standing completely submerged on the bottom of a swimming pool, in 3.0 m of water. you are sitting on the end of the diving board, almost directly over her.

    James

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    get a 1.8-m-tall diver is standing completely submerged on the bottom of a swimming pool, in 3.0 m of water. you are sitting on the end of the diving board, almost directly over her. from EN Bilgi.

    A 150

    Find step-by-step Physics solutions and your answer to the following textbook question: A 150-cm-tall diver is standing completely submerged on the bottom of a swimming pool full of water. You are sitting on the end of the diving board, almost directly over her. How tall does the diver appear to be?.

    Question

    A 150-cm-tall diver is standing completely submerged on the bottom of a swimming pool full of water. You are sitting on the end of the diving board, almost directly over her. How tall does the diver appear to be?

    Explanation

    Verified

    1 Concepts and Principles

    An image can be formed by refraction from a planar surface. The object and image distances for refraction from such a surface are related by

    \begin{gather*} s'=-\dfrac{n_2}{n_1}s\tag{*} \end{gather*}

    s ′ =− n 1 ​ n 2 ​ ​ s ​ (*) ​

    The minus sign tells us that we have a virtual image.

    n_1 n 1 ​

    is the index of refraction of the medium of the object,

    n_2 n 2 ​

    is the index of refraction of the medium of the observer, distance

    s

    s is called the object distance, and

    s' s ′

    the image distance, where

    s s and s' s ′

    are measured from the boundary.

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    Submerged Diver Apparent Height

    Homework Statement A 151 -tall diver is standing completely submerged on the bottom of a swimming pool full of water. You are sitting on the end of the...

    Forums Homework Help

    Introductory Physics Homework Help

    Submerged Diver Apparent Height

    Thread starter Nevertheless Start date Feb 4, 2010 Feb 4, 2010 #1 Nevertheless

    Homework Statement

    A 151 -tall diver is standing completely submerged on the bottom of a swimming pool full of water. You are sitting on the end of the diving board, almost directly over her. How tall does the diver appear to be?

    Homework Equations

    n1sin theta1= n2 sin theta2 ??

    The Attempt at a Solution

    Honestly I do not even know where to begin... so any help will be greatly appreciated!

    Answers and Replies

    Feb 4, 2010 #2 kuruman

    What do you know about apparent depth? The diver's head is at an apparent depth and so are her feet. The difference between apparent depths is the diver's apparent height.

    Feb 5, 2010 #3 Nevertheless

    So after reading my book I found something that talks about a diver. The problem is it talks about finding the diameter of the circle of which you can see in the water. D= 2h tan theta c. Theta c= sin^-1 (1.00/1.33) for the water air boundary and h is the depth of water. This is all I can find even close to the problem in the book. In the problem however we are not given any information about the angle just that he is right above. If he is at at 90 degree angle I don't see how he can tell a height at all. He would just see his head. I don't have any information about the depth of the water or the apparent depth of the diver. So I am really frustrated with this problem.

    Feb 6, 2010 #4 kuruman

    Try doing some research on the web on "apparent depth". Here is an example of what you might find

    http://www.physicstutorials.org/index.php/home/optics/refraction-of-light/apparent-depth-real-depth

    Feb 6, 2010 #5 Nevertheless

    THANK YOU SO MUCH. I seriously have tried everything! I am really confused on why my book does not have the formula in it. But thank you again.

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    Introductory Physics Homework Help

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    SOLVED:A 1.8

    VIDEO ANSWER: in this question way have, ah, swimming pool. Um, they treat me the, uh k. So this fool is completely filled with water treatment. This need. Okay, at 1.8 m, Devo is in sight. Uh huh. And face, someon

    Source : www.numerade.com

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    James 8 month ago
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    Guys, does anyone know the answer?

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