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# a 2-kg ball b is traveling horizontally at 10 m/s when it strikes 2-kg ball a. ball a is initially at rest and is attached to a spring with constant 100 n/m and an unstretched length of 1.2 m. knowing the coefficient of restitution between a and b is 0.8 and friction between all surfaces is negligible, determine the normal force between a and the ground when it is at the bottom of the hill.

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### James

Guys, does anyone know the answer?

get a 2-kg ball b is traveling horizontally at 10 m/s when it strikes 2-kg ball a. ball a is initially at rest and is attached to a spring with constant 100 n/m and an unstretched length of 1.2 m. knowing the coefficient of restitution between a and b is 0.8 and friction between all surfaces is negligible, determine the normal force between a and the ground when it is at the bottom of the hill. from EN Bilgi.

## A 2

A 2-kg ball B is traveling horizontally at 10 m/s when it strikes 2-kg ball A. Ball A is initially at rest and is attached to a spring with constant 100 N/m and an unstretched length of 1.2 m. Knowing the coefficient of restitution between A and B is 0.8 and friction between all surfaces […] ## Question:

Vector Mechanics for Engineers: Dynamics-Solution Manual [EXP-4784]

A 2-kg ball B is traveling horizontally at 10 m/s when it strikes 2-kg ball A. Ball A is initially at rest and is attached to a spring with constant 100 N/m and an unstretched length of 1.2 m. Knowing the coefficient of restitution between A and B is 0.8 and friction between all surfaces is negligible, determine the normal force between A and the ground when it is at the bottom of the hill. ## Report Solution

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## A 2

Answer:Explanation:We firstly determine the impulse momentum of ball B in tangential direction.Then we simplify the equation for impulse momentum for tiny-mole  1 year ago 9

## A 2-kg ball B is traveling horizontally at 10 m/s when it strikes 2-kg ball A. Ball A is initially at rest and is attached to a

spring with constant 100 N/m and an unstretched length of 1.2 m. Knowing the coefficient of restitution between A and B is 0.8 and friction between all surfaces is negligible, determine the normal force between A and the ground when it is at the bottom of the hill.

Liono4ka [1.6K]1 year ago

4 0

We firstly determine the impulse momentum of ball B in tangential direction.

Then we simplify the equation for impulse momentum for ball A and ball B.

Now the equation for coefficient of restitution is determined to solve above equation with 2 equations 2 unknowns.

Hence,

Now we apply Conservation of Energy Principle. Finally, we apply Newton's 2nd Law. You might be interested in

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The correct answer is b pascal

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## A 2

A 2-kg ball B is traveling horizontally at 10 m/s when it strikes 2-kg ball A. Ball A is initially at rest and is attached to a spring with constant 100 N/m and an unstretched length of 1.2 m. Knowing the coefficient of restitution between A and B is 0.8 and friction between all surfaces is negligible, determine the

Textbooks / Engineering and Tech / Vector Mechanics for Engineers: Dynamics 10 / Chapter 13 / Problem 13.199

## A 2-kg ball B is traveling horizontally at 10 m/s when it

ISBN: 9780073398136 114

## Solution for problem 13.199 Chapter 13

Vector Mechanics for Engineers: Dynamics | 10th Edition

Get Full Solutions 399 Reviews 28 0 Problem 13.199

A 2-kg ball B is traveling horizontally at 10 m/s when it strikes 2-kg ball A. Ball A is initially at rest and is attached to a spring with constant 100 N/m and an unstretched length of 1.2 m. Knowing the coefficient of restitution between A and B is 0.8 and friction between all surfaces is negligible, determine the normal force between A and the ground when it is at the bottom of the hill.

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