if you want to remove an article from website contact us from top.

# a double-slit experiment is performed with light of wavelength 600 nm . the bright interference fringes are spaced 1.8 mm apart on the viewing screen.

Category :

### James

Guys, does anyone know the answer?

get a double-slit experiment is performed with light of wavelength 600 nm . the bright interference fringes are spaced 1.8 mm apart on the viewing screen. from EN Bilgi.

## A double

Find step-by-step Physics solutions and your answer to the following textbook question: A double-slit experiment is performed with light of wavelength 600 nm. The bright interference fringes are spaced 1.8 mm apart on the viewing screen. What will the fringe spacing be if the light is changed to a wavelength of 400 nm?.

### Question

A double-slit experiment is performed with light of wavelength 600 nm. The bright interference fringes are spaced 1.8 mm apart on the viewing screen. What will the fringe spacing be if the light is changed to a wavelength of 400 nm?

### Explanation

Verified \textbf{Given:} Given:

\color{#4257b2}\bullet \bullet

∙∙ \lambda_1=600 λ 1 ​ =600 nm

=\color{#c34632}600\times10^{-6}

=600×10 −6 m

\color{#4257b2}\bullet \bullet

∙∙ \Delta y_1=1.8 Δy 1 ​ =1.8 mm

=\color{#c34632}1.8\times10^{-3}

=1.8×10 −3 m

\color{#4257b2}\bullet \bullet

∙∙ \lambda_2=400 λ 2 ​ =400 nm

=\color{#c34632}400\times10^{-6}

=400×10 −6 m

\color{#4257b2}\bullet \bullet

∙∙ d_1=d_2 d 1 ​ =d 2 ​

\color{#4257b2}\bullet \bullet

∙∙ L_1=L_2 L 1 ​ =L 2 ​

## Create a free account to see explanations

Already have an account?

### Related questions

PHYSICS

A double-slit experiment is performed with light of wavelength 630 nm. The bright interference fringes are spaced 1.8 m m apart on the viewing screen. What will the fringe spacing be if the light is changed to a wavelength of 420 nm?

PHYSICS

A double slit is illuminated simultaneously with orange light of wavelength 600 nm and light of an unknown wavelength. The m = 4 bright fringe of the unknown wavelength overlaps the m = 3 bright orange fringe. What is the unknown wavelength?

PHYSICS

Light of two different wavelengths is used in a double-slit experiment. The location of the third-order maximum for the first light, yellow-orange light

(\lambda=600\ \mathrm{nm}),

(λ=600 nm), coincides with the location of the fourth-order maximum for the other color's light. What is the wavelength of the other light?

PHYSICS

A double-slit interference experiment is performed with red light and then again with blue light. In what ways do the two interference patterns differ? (Hint: Consider the difference in wavelength for the two colors of light.)

Source : quizlet.com

## A double

Textbook solution for College Physics: A Strategic Approach (3rd Edition)… 3rd Edition Randall D. Knight (Professor Emeritus) Chapter 17 Problem 10P. We have step-by-step solutions for your textbooks written by Bartleby experts!

Textbook Question

Chapter 17, Problem 10P

A double-slit experiment is performed with light of wavelength 600 nm. The bright interference fringes are spaced 1.8 mm apart on the viewing screen. What will the fringe spacing be if the light is changed to a wavelength of 400 nm?

Expert Solution & Answer

### Want to see the full answer?

Check out a sample textbook solution

SEE SOLUTION 03:54 Previous

Chapter 17, Problem 9P

Next

Chapter 17, Problem 11P

Want to see this answer and more?

Experts are waiting 24/7 to provide step-by-step solutions in as fast as 30 minutes!*

*Response times may vary by subject and question complexity. Median response time is 34 minutes for paid subscribers and may be longer for promotional offers.

### Additional Science Textbook Solutions

Find more solutions based on key concepts

89. One example of a water system is a garden hose that waters a garden. Another is the cooling system of an au...

Conceptual Physical Science (6th Edition)

A spherical asteroid with radius r = 123 m and mass M = 2.25 × 1010 kg rotates about an axis at four revolution...

Physics for Scientists and Engineers with Modern Physics

A satellite can orbit at 5km above the Moon but not at 5km above the Earth. Why?

Conceptual Integrated Science

31.49 An L-R-C series circuit is connected to an ac source of constant voltage amplitude V and variable angular...

University Physics with Modern Physics (14th Edition)

Express the unit vectors in terms of (that is, derive Eq. 1.64). Check your answers several ways Also work o...

Introduction to Electrodynamics

A 40-W fluorescent lamp has power factor 0.85 and operates from the 120-V rms AC power line. How much current d...

Essential University Physics (3rd Edition)

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Concept explainers Article

Diffraction of light

In physics, the term diffraction is defined as the bending of light around the corners of the obstacle. As a light ray passes by an aperture, it bends around the edges or through slits, it spreads out through a narrow openin…

Similar questions

A double-slit experiment has a slit separation distance of 0.08 mm.  If the bright interference fringes are to be spaced 5 mm apart on the screen when the slits are illuminated with a laser of wavelength 633 nm, what should be the distance to the screen from the slits? a) 0.42 m b) 0.63 m c) 0.77 m d) 0.81 m e) 0.92 m

In a Young's double slit experiment, the separation between the slits is 1.20 x 10-4 m; and the screen is located 3.50 m from the slits. The distance on the screen between the central bright fringe and the second order bright fringe is 4.15 cm. What is the frequency of the light used in this experiment? (Given: ? =3.0×108 ?/?)

In a Young's double slit experiment the slit separation is 0.4 mm and the distance between the screen and the slit is 120 cm. If the 3rd dark fringe formed at 0.5 cm from the central bright fringe. Find the wavelength of the light in cm. (a) 6.6 × 10-7 cm (b) 3.3 × 10-5 cm (c) 4.5 × 10-4 cm (d) 5.5 × 10-3 cm

In a Young's double-slit experiment, light of wavelength 562 nm illuminates two slits which are separated by 1.00 mm. Bright fringes are seen on a screen at a distance of 5.00 m from the slits. Calculate the separation distance in units of mm, between adjacent bright fringes.

In a Young's double-slit experiment, the angle that locates the second dark fringe on either side of the central bright fringe is 7.2 . Find the ratio of the slit separation to the wavelength of the light.

Light of wavelength 500 nm diffracts through a slit of width 2.00 mm and onto a screen that is 2.00 m away. On the screen, what is the distance between the center of the diffraction pattern and the third diffraction minimum?

SEE MORE QUESTIONS

Need a deep-dive on the concept behind this application? Watch these videos for an in-depth look

Diffraction of light animation best to understand class 12 physics

PTAS: Physics Tomorrow Ambition School

Recommended textbooks for you Physics for Scientists and Engineers: Foundations...

Physics ISBN: 9781133939146 Author: Katz, Debora M. Publisher: Cengage Learning SEE MORE TEXTBOOKS

Diffraction of light animation best to understand class 12 physics; Author: PTAS: Physics Tomorrow Ambition School;

About FAQ Honor Code Academic Integrity Sitemap Careers

Refer a Friend

Contact Research (Essays)

High School Textbooks

Literature Guides

Concept Explainers by Subject

Source : www.bartleby.com

## A double slit experiment is performed with light of wavelength 500 nm. A thin film of thickness 2 pm and refractive index 1.5 is introduced in the path of the upper beam. The location of the central maximum will :

Click here👆to get an answer to your question ✍️ A double slit experiment is performed with light of wavelength 500 nm. A thin film of thickness 2 pm and refractive index 1.5 is introduced in the path of the upper beam. The location of the central maximum will : Question

A

B

C

D

## Shift downward by its fringes

Medium Open in App Solution Verified by Toppr

Correct option is C)

In Young's Double Slit Experiment (YDSE) be the position of central bright fringe on the screen in absence of any film, because the S

1 ​ O=S 2 ​ O.

When we introduce a film of thickness t and refractive index p, an additional path difference equal to (μt−t)=(μ−1)t is introduced. The optical path of upper bean becomes longer. For path difference on screen to be zero, path from lower slit S

2 ​

should also be more. Thus, central bright fringe wire be located some what at O' as S

2 ​ O ′ >S 2 ​ O.

∴ The fringe pattern shifts upwards.

Now as a change in path difference of λ corresponds to a change in position on the screen by β=

d D ​ λ

Change in optical path difference Δy=(μ−1)t×

d D ​ Δy=(1.5−1)(2×10 −6 ) d D ​ Δy= 2 1 ​ ×2×10 −6 d D ​ = d D ​ ×10 −6 m Fringe width = d D ​ λ= d D ​ ×100×10 −9 m=β Clearly, β Δy ​ = d D ​ ×500×10 −9 d D ​ ×10 −6 ​ =2 = 500×10 −9 10 −6 ​ = 500 10 −6 ×10 9 ​ = 500 10 3 ​ ∴Δy=2β Video Explanation Solve any question of Wave Optics with:-

Patterns of problems

>